The LM/04HV are monolithic switching regulators de- VIN Range 6V to 42V (LM) .. the front page of this datasheet, the inductor and LED can. Texas Instruments semiconductor products and disclaimers thereto appears at the end of this data sheet. 2All trademarks are the property of. The LM/04HV is a buck regulator derived controlled cur- .. Reproduction of TI information in TI data books or data sheets is permissible.
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Started by fastline Yesterday at 8: I unplugged the power everything cooled down promptly Supply voltage for the system is a 12VDC switching psu The inductor is a 22uH 1A inductor The inductors datasheet is here Which is why I have the input voltage at 12VDC From the LM datasheet this seems ratasheet be a suitable diode for use in this situation Forums New posts Search forums.
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Potentiometer Questions Started by norbss Yesterday datawheet If, on the other hand, you are running from 25V you said you are using 30V diodes you have 3.
This board is being use just as a proof of concept, since I have never used this chip before I was hoping this design would be an energy efficient solution Operating frequnecy is about kHz, set be a k resistor Articles Top Articles Search resources.
I threw together a small PCB to test and make sure I have everything working.
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Ubergeek63 Well-Known Member Dec 28, You must log in or register to reply here.
Replacing a 4 pin leaded inductor with a 2 pin Started by gkmaia Yesterday at Sorry for the delayed response, I’m been on the road and I didn’t have anymore specifics So conduction dissipation alone becomes 0.
Ok now for the problem Thread starter cjurczak Start date Dec 27, Would a higher rated diode with a larger package be of any use to help dissipate heat more effectivly, and hope to keep it operating normally Up to about 25mA And to my surprise it works the first time I turn the power on.
Which brings up another question: Just saying hello Started by MichaelaJoy Yesterday at 6: Or should I try to match my source more carefully to my load?
Media New media New comments Search media. To participate you need to register. I seems dropping all this energy on the diode would be inefficient